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Bloodstained Ritual of the Night: Can You Play as Zangetsu? Everything You Need to Know

can you play as zangetsu in bloodstained ritual of the night
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Bloodstained Ritual of the Night: Can You Play as Zangetsu? Everything You Need to Know

Zangetsu is the beloved protagonist from the first Bloodstained title, Curse of the Moon. While he’s hostile to Miriam (the protagonist) this time around, players may be wondering exactly what they need to do, or if it’s even possible to play as Zangetsu. Here’s what we know about playing as this fan-favorite character in Ritual of the Night.

Can You Play as Zengatsu in Ritual of the Night Right Now?

Unfortunately, at this moment in time, it’s not possible to play as Zengatsu, but that doesn’t mean it’s going to stay this way forever. It’s been noted that the first game’s protagonist will come to Ritual of the Night as a playable character in a post-launch update.

The bad news, though, is that there’s no official word on exactly when this update will arrive, and with players noting a number of bugs, including a game-breaking Silver Bromide bug, the developers will likely address these issues before releasing any additional content to Bloodstained: Ritual of the Night.

The news was shared in the “2nd Playable Character Reveal” trailer that we’ve included down below. Here, we can see Zangetsu in action, voiced by David Hayter, using his Zangetsuto katana as he slices his way through countless demons.

Sadly, the trailer ends with a rather vague announcement that the character will come to Bloodstained “free after launch.”

As soon as the update is released and Zangetsu becomes a playable character, we’ll update this guide with a new section on how to play as the demon hunter on your adventure through Ritual of the Night.

For now, though, just sit tight and keep those fingers crossed the update comes sooner rather than later.

For more tips, tricks, and guides on Bloodstained: Ritual of the Night, be sure to check out some of our most popular guides down below, or search for Twinfinite.

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